Thursday, March 22, 2007

PHP4 reference example 2


<?php
function refArgs(&$v)
{
$x = &$v;
echo "old x value: " . $x;
echo "<br />";
$x = "new x value.";
}
$old_x = "old x value.";
refArgs($old_x);
echo "new x value: " . $old_x;
//old x value: old x value.
//new x value: new x value.
//通过reference引用&$v,$old_x 和 $x 其实就是指向一个相同的对象。
?>

No comments :